8 Hero- Don-t Just Focus On Clearing The Tower -v...THERE ARE TWO special triangles in trigonometry. One is the 30°-60°-90° triangle. The other is the isosceles right triangle. They are special because with simple geometry we can know the ratios of their sides, and therefore solve any such triangle. Theorem. In a 30°-60°-90° triangle the sides are in the ratio
1 : 2 :
We will prove that below. Note that the smallest side, 1, is opposite the smallest angle, 30°; while the largest side, 2, is opposite the largest angle, 90°. (Theorem 6). (For, 2 is larger than The cited theorems are from the Appendix, Some theorems of plane geometry. Here are examples of how we take advantage of knowing those ratios. First, we can evaluate the functions of 60° and 30°. Example 1. Evaluate cos 60°. Answer. For any problem involving a 30°-60°-90° triangle, the student should not use a table. The student should sketch the triangle and place the ratio numbers. Since the cosine is the ratio of the adjacent side to the hypotenuse, we can see that cos 60° = ½. Example 2. Evaluate sin 30°. Answer. According to the property of cofunctions, sin 30° is equal to cos 60°. sin 30° = ½. On the other hand, you can see that directly in the figure above. Problem 1. Evaluate sin 60° and tan 60°. To see the answer, pass your mouse over the colored area. The sine is the ratio of the opposite side to the hypotenuse.
The tangent is ratio of the opposite side to the adjacent.
Problem 2. Evaluate cot 30° and cos 30°.
The cotangent is the ratio of the adjacent side to the opposite.
= Or, more simply, cot 30° = tan 60°. As for the cosine, it is the ratio of the adjacent side to the hypotenuse. Therefore,
Before we come to the next Example, here is how we relate the sides and angles of a triangle:
If an angle is labeled capital A, then the side opposite will be labeled small a. Similarly for angle B and side b, angle C and side c. Example 3. Solve the right triangle ABC if angle A is 60°, and side AB is 10 cm.
Solution. To solve a triangle means to know all three sides and all three angles. Since this is a right triangle and angle A is 60°, then the remaining angle B is its complement, 30°. Again, in every 30°-60°-90° triangle, the sides are in the ratio 1 : 2 : When we know the ratios of the sides, then to solve a triangle we do not require the trigonometric functions or the Pythagorean theorem. We can solve it by the method of similar figures. Now, the sides that make the equal angles are in the same ratio. Proportionally, 2 : 1 = 10 : AC. 2 is two times 1. Therefore 10 is two times AC. AC is 5 cm. The side adjacent to 60°, we see, is always half the hypotenuse. As for BC—proportionally, 2 : To produce 10, 2 has been multiplied by 5. Therefore, In other words, since one side of the standard triangle has been multiplied by 5, then every side will be multiplied by 5.
1 : 2 : Compare Example 11 here. Again: When we know the ratio numbers, then to solve the triangle the student should use this method of similar figures, not the trigonometric functions. (In Topic 10, we will solve right triangles whose ratios of sides we do not know.) Problem 3. In the right triangle DFE, angle D is 30° and side DF is 3 inches. How long are sides d and f ?
The student should draw a similar triangle in the same orientation. Then see that the side corresponding to
Therefore, each side will be multiplied by Problem 4. In the right triangle PQR, angle P is 30°, and side r is 1 cm. How long are sides p and q ?
The side corresponding to 2 has been divided by 2. Therefore, each side must be divided by 2. Side p will be ½, and side q will be ½ Problem 5. Solve the right triangle ABC if angle A is 60°, and the hypotenuse is 18.6 cm.
The side adjacent to 60° is always half of the hypotenuse -- therefore, side b is 9.3 cm. Problem 6. Prove: The area A of an equilateral triangle whose side is s, is A = ¼
The area A of any triangle is equal to one-half the sine of any angle times the product of the two sides that make the angle. (Topic 2, Problem 6.) In an equilateral triangle each side is s , and each angle is 60°. Therefore, A = ½ sin 60°s2. Since sin 60° = ½ A = ½· ½ Problem 7. Prove: The area A of an equilateral triangle inscribed in a circle of radius r, is
Hero- Don-t Just Focus On Clearing The Tower -v..."Hero, don't just focus on clearing the tower." This kind of advice is typically given to players to encourage a more strategic approach to the game rather than focusing solely on immediate objectives like destroying enemy towers. Here are a few reasons why this advice is valuable:
In essence, the advice encourages players to think about the broader strategy of the game, consider their role within their team, and balance their immediate actions with long-term strategic goals. Common mistakes to avoid
Hero: Don’t Just Focus on Clearing the Tower – Value Every Step of the JourneyIn nearly every role-playing game (RPG) or gacha game, the "Tower" stands as the ultimate proving ground. It looms on the horizon—a spire of challenge, reward, and prestige. Players spend weeks optimizing teams, farming artifacts, and studying enemy patterns, all with one obsessive mantra: Clear the Tower. But fixating solely on the summit is a trap. The most seasoned players—the true heroes—know a secret that leaderboards often obscure: The journey through the Tower is more valuable than the act of clearing it. Hero- don-t just focus on clearing the tower -v... 4. Remember the StoryMany Towers hide narrative fragments—letters, flashbacks, environmental details. Rushing skips them. The hero who reads every stone on the path understands why they fight. Purpose fuels persistence longer than any reward screen. Example micro-build plans
The “Tower Blindness” SyndromeLet’s define the problem. “Tower Blindness” is the player tendency to evaluate every decision based on a single metric: Can this clear the next floor? This manifests in three toxic behaviors:
Here’s what the games don’t tell you: the tower is a distraction. A shiny, vertical ladder meant to keep you chasing numbers. The real game—the strategic depth, the hidden bonuses, the unbreakable team synergies—lives in the stories of your heroes. The LessonSo, Hero, take a breath. You have your sword, your spell, or your spreadsheet. You are ready to conquer. But as you stand before that final gate, ask yourself: Am I just trying to escape this tower, or am I mastering it? Don't just clear the level. Learn the lesson. Because trust me—there is always another tower. What is the "tower" you are currently climbing? Are you focused on the finish line, or the journey? Let me know in the comments. , specifically focusing on the philosophy that you shouldn't just "clear" the tower, but rather focus on farming and long-term utility. The Fundamental Philosophy In this game, "clearing" a tier isn't the primary goal. Your true objective is economy and efficiency "Hero, don't just focus on clearing the tower . If you rush to higher tiers too quickly, you may find that your coin income drops because you can't survive enough waves to benefit from multipliers. Early Game Strategy (Tier 1) Prioritize Utility : Focus your workshop upgrades on Cash Bonus Coins/Kill . Economy is the foundation of all growth. The "Def Abs" Trap Defense Absolute are extremely effective for "skyrocketing" through Tier 1. However, Defense Absolute becomes useless once you move to Tier 2 and beyond, so don't over-invest in it long-term. Survival Stats : As you progress, transition your focus to to survive boss hits. The "Blender" Strategy The most effective way to survive high waves is the "Blender" build, which focuses on keeping enemies away from your tower rather than just tanking damage. Knockback & Attack Speed : Pushes enemies away from your tower. : These will kill almost every common enemy instantly if they are pushed into the orb line. Multi-Shot : Helps manage large crowds so your knockback stays effective. The Lab & Ultimate Weapons (UW) Unlock All 5 Labs ASAP : Lab progress is the most important long-term growth mechanic. Spend your gems here first before buying too many cards. The Golden Duo Golden Tower (GT) Black Hole (BH) are the two most important Ultimate Weapons. Prioritize getting Golden Tower first if it appears. Synchronizing the cooldowns of GT and BH creates a massive coin multiplier that is essential for late-game progress. When to Move Tiers Don't move to Tier 2 just because you reached wave 100. The 1000 Wave Rule : You should stay in Tier 1 until you can consistently reach Coin Check : Transition to Tier 2 only when you can reach roughly there, as this is usually the point where Tier 2 becomes more profitable for coins than Tier 1. card combinations for farming? Map Control : Focusing solely on towers can In Hero Wars, the "don’t just focus on clearing the tower" strategy advises against rapidly increasing Team Level, as tower difficulty scales with player level and can lead to a "difficulty trap". To successfully climb, players should focus on maxing a small core team, utilizing manual control for energy management, and using the retreat trick to keep heroes alive for daily rewards. Detailed tips are available in the Hero Wars Wiki and on the Hero Wars - Dominion Era Zendesk It looks like you’re trying to share or refine a piece of advice for a game strategy, likely related to a tower-climb or rogue-like genre. While "Hero—don't just focus on clearing the tower" could also refer to a metaphorical "hero's journey" or a specific anime/manga quote, I'll assume you are looking for a stronger version of this gaming tip. Here are a few ways to punch up that text depending on the "vibe" you want: The Strategic Approach: "Hero—don’t just focus on clearing the tower; prioritize resource management and buff synergy to survive the higher floors." The Dramatic Approach: "Hero, do not mistake reaching the summit for victory. If you ignore the relics along the way, the tower will eventually become your tomb." The Short & Punchy Version: "Focusing only on the climb is a rookie mistake. A true hero farms the floors before facing the peak." Was this meant to be a tip for a specific game like AFK Journey or Tower of God, or were you looking for a more thematic/story-driven rewrite? Example (worked)Scenario: Repeated bugs after weekly deploys.
Typical decision checklist (each floor/node)
Problem 8. Prove: The angle bisectors of an equilateral triangle meet at a point that is two thirds of the distance from the vertex of the triangle to the base.
Let ABC be an equilateral triangle, let AD, BF, CE be the angle bisectors of angles A, B, C respectively; then those angle bisectors meet at the point P such that AP is two thirds of AD. First, triangles BPD, APE are congruent.
For, since the triangle is equilateral and BF, AD are the angle bisectors, then angles PBD, PAE are equal and each
30°; Angles PDB, AEP then are right angles and equal. Therefore, triangles BPD, APE are congruent.
Therefore, BP = 2PD.
But AP = BP, because triangles APE, BPD are conguent, and those are the sides opposite the equal angles. The proof Here is the proof that in a 30°-60°-90° triangle the sides are in the ratio 1 : 2 : Draw the equilateral triangle ABC. Then each of its equal angles is 60°. (Theorems 3 and 9)
Draw the straight line AD bisecting the angle at A into two 30° angles. Now, since BD is equal to DC, then BD is half of BC. This implies that BD is also half of AB, because AB is equal to BC. That is, BD : AB = 1 : 2 From the Pythagorean theorem, we can find the third side AD:
Therefore in a 30°-60°-90° triangle the sides are in the ratio 1 : 2 : Corollary. The square drawn on the height of an equalateral triangle is three fourths of the square drawn on the side. Next Topic: The Isosceles Right Triangle Please make a donation to keep TheMathPage online. Copyright © 2022 Lawrence Spector Questions or comments? |