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A standard PDF might show: hf = f (L/D) (v²/2g)
A better PDF will provide a solved example for a real-world scenario: "Size a 200-foot carbon steel line pumping 500 GPM of crude oil at 120°F with a maximum allowable pressure drop of 10 psi." It will walk you through friction factor (using Moody’s chart or Swamee-Jain formula) and then show you how to iterate between nominal pipe sizes (NPS).
Typical module 3 documents often:
A better PDF would start with one key question: What happens if I pick the wrong diameter?
| If you oversize | If you undersize | |----------------|------------------| | Higher material cost | Excessive pressure drop | | Heavier supports | Higher pumping energy | | Larger insulation | Erosion/corrosion risk | | Unnecessary capital expense | Noise & vibration |
The sweet spot lies in balancing hydraulic performance with pressure integrity. This article is structured to rank for search
Assume a pipe carries seawater at 100°F, 500 psig, NPS 6, SA-106 Gr B (S = 20,000 psi at 100°F).
Calculation without corrosion allowance (a bad PDF): t = (500 * 6.625) / (2*(20,00011 + 500*0.4)) = 0.082 inches. Choose Sch 10 (0.134 in).
Calculation with 1/8" corrosion allowance (a better PDF): t = 0.082 + 0.125 = 0.207 inches. Now you need Sch 80 (0.432 in) or Sch 40 (0.280 in). The Darcy-Weisbach Equation: Your Best Friend A standard
The "Better" Lesson: Ignoring corrosion allowance is the #1 cause of premature pipe failure in refineries.
In Module 3, sizing must also account for integrity. For two-phase flow or slurries, velocity limits are governed by erosion. If the fluid is corrosive, the sizing must include a corrosion allowance (extra wall thickness), which slightly reduces the internal diameter and affects hydraulics.