Soalan Penyelesaian Masalah Operasi Bergabung Matematik Tahun 5 //top\\ Here

Berikut adalah set soalan penyelesaian masalah Matematik Tahun 5 yang melibatkan operasi bergabung (tambah, tolak, darab, dan bahagi) termasuk penggunaan tanda kurung: Koleksi Soalan Penyelesaian Masalah Operasi Bergabung

Soalan 1Sebuah kilang menghasilkan 45,600 biji guli. Guli-guli itu dimasukkan ke dalam 80 buah kotak secara sama rata. Jika 15 buah kotak dihantar ke Kedai A, berapakah jumlah guli yang diterima oleh Kedai A?

Soalan 2Puan Aminah membeli 5 kotak epal. Setiap kotak mengandungi 48 biji epal. Dia mendapati 12 biji epal telah rosak dan membuangnya. Bakinya diagihkan sama rata kepada 6 orang jirannya. Berapakah biji epal yang diterima oleh setiap jiran?

Soalan 3Sebuah gudang mempunyai 125,000 buah buku. Sebanyak 18,500 buah buku telah didermakan. Baki buku itu kemudiannya ditambah dengan 4,200 buah buku baru. Jika semua buku itu hendak disusun ke dalam rak yang boleh memuatkan 100 buah buku setiap satu, berapakah bilangan rak yang diperlukan? Soalan 4Hitung hasil bagi:

.Situasi: Sebuah syarikat memberikan bonus RM14 kepada setiap 20,000 orang pekerjanya (hasil tambah dua kumpulan pekerja). Berapakah jumlah besar bonus yang perlu dibayar?

Soalan 5Sebuah bakul besar mengandungi 1,200 batang pensel. Seorang pemborong membeli 25 bakul tersebut. Dia kemudian membungkus semula pensel itu ke dalam paket-paket kecil yang mengandungi 12 batang pensel setiap satu. Berapakah jumlah paket kecil yang terhasil? Tips Menyelesaikan Masalah (Langkah-Langkah):

Baca dan Garis: Kenal pasti maklumat penting (nombor) dan kata kunci operasi. Soalan 1: Membeli Barang di Kedai Buku

Susun Ayat Matematik: Pastikan kedudukan operasi betul. Ikut hukum KUDA BATO (Kurung, Darab/Bahagi, Tambah/Tolak). Selesaikan: Kira dengan teliti mengikut urutan.

Adakah anda mahukan skema jawapan lengkap untuk soalan-soalan di atas?

Amin and the Quest for the Golden Calculator Amin sat at his wooden desk, staring at a math problem that looked more like a puzzle than a calculation. His teacher, Cikgu Sarah, had given the class a special challenge called the Mystery of the Combined Operations. To solve it, Amin had to remember the sacred law of mathematics: BODMAS.

He looked at the first clue written on a dusty parchment: 450 + 25 × 4 – 120.

Amin’s first instinct was to add 450 and 25, but then he remembered the rule. Multiplication must come first! He whispered to himself, 25 times 4 is 100. Now the puzzle looked simpler: 450 + 100 – 120. He added the numbers to get 550, then subtracted 120. The answer was 430. As he wrote the number down, a hidden compartment in his desk clicked open, revealing a small silver key.

The second clue required him to handle a bracket: (1,200 – 300) ÷ 6 + 45. Amin membeli 3 batang pen pada harga RM4

Amin knew that whatever was inside the brackets had the highest priority. 1,200 minus 300 gave him 900. Next, he had to deal with the division before the addition. 900 divided by 6 was 150. Finally, he added 45 to get 195. He ran to the back of the classroom where a small wooden chest sat. He inserted the silver key and turned it.

Inside the chest wasn’t gold or jewels, but a shiny Golden Calculator and a note from Cikgu Sarah. It read: Logic and order are the true treasures of the mind. Amin smiled, realizing that math wasn't just about numbers; it was about following the right steps to find the truth. He felt like a real explorer, ready to conquer any problem Year 5 could throw at him. 💡 Key Rules for Combined Operations (Tahun 5)

To solve these problems like Amin, always follow the order of KUDABATAS (Kurungan, Darab, Bahagi, Tambah, Tolak): Kurungan (): Solve everything inside brackets first. Darab (×) & Bahagi (÷): Solve from left to right. Tambah (+) & Tolak (-): Solve from left to right. A step-by-step guide for more complex word problems?

To change the theme of the story (e.g., space adventure or Minecraft)?

Soalan 1: Membeli Barang di Kedai Buku

Amin membeli 3 batang pen pada harga RM4 sebatang dan 2 buah buku pada harga RM7 sebuah. Dia membayar dengan wang kertas RM50. Berapakah baki wang Amin?

Penyelesaian:

  1. Jumlah harga pen: 3 × RM4 = RM12
  2. Jumlah harga buku: 2 × RM7 = RM14
  3. Jumlah belian: RM12 + RM14 = RM26
  4. Baki wang: RM50 – RM26 = RM24

Ayat matematik:
50 – (3 × 4 + 2 × 7) = 50 – (12 + 14) = 50 – 26 = 24

Jenis 2: Bahagi dan Tolak

Soalan:
Hasna mempunyai 240 biji guli. Dia menyusun guli tersebut ke dalam 8 buah balang sama banyak. Kemudian, dia memberikan 5 biji guli daripada setiap balang kepada adiknya. Berapakah baki guli dalam setiap balang sekarang?

Langkah Penyelesaian:

Jawapan: Setiap balang kini berisi 25 biji guli.

Question 1: The Bulk Purchase (Multiplication & Subtraction)

Soalan: Di sebuah kedai buku, harga sebatang pen ialah RM5. Puan Aina membeli 10 batang pen. Dia membayar dengan wang kertas RM100. Berapakah baki wang yang Puan Aina terima?

(Translation: A pen costs RM5. Puan Aina buys 10 pens. She pays with RM100. How much change does she receive?) Soalan: Di sebuah kedai buku

Step-by-step solution:

  1. Identify operations: Total cost (Multiplication) then change (Subtraction).
  2. Calculate total cost: ( 10 \times RM5 = RM50 )
  3. Calculate balance: ( RM100 - RM50 = RM50 )
  4. Answer: RM50